http://southking.iteye.com/blog/1489462

假设两个ViewController之间已经建立了Segue

A:TableViewController的子类   B:viewController  A --> B 传送数据类Player的对象player

1.设置Segue的identifier

2.在B.h里添加

@property(nonatomic,strong) Player *player;

   在B.m里添加

 

@synthesize player;

3.在A.m里重写UIViewController 的以下方法

 

-(void) prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender{
    UIViewController *destination = segue.destinationViewController;
    if ([destination respondsToSelector:@selector(setPlayer:)]){       //判断目标是否存在setPlayer方法
        [destination setValue:selectedPlayer forKey:@"player"];
    }
}

4.在A.m里重写

 

- (NSIndexPath *)tableView:(UITableView *)tableView willSelectRowAtIndexPath:(NSIndexPath *)indexPath{
    selectedPlayer = [players objectAtIndex:indexPath.row];
    return indexPath;
}

   说明：之所以不重写

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath;

是因为执行顺序，不然会取不到值：

willSelectRowAtIndexPath --> prepareForSegue --> didSelectRowAtIndexPath

 

5.OK，传送成功！在B里已经可以用player对象了。